SQL Server - How to find the nth Highest salary from Employee Table

CREATE TABLE Employee_Test
(
    Employee_ID INT,
    Employee_name Varchar(100),
    Employee_Salary Decimal (10,2)
);
INSERT INTO Employee_Test VALUES (1,'Anish',1000);
INSERT INTO Employee_Test VALUES (2,'Sushant',1200);
INSERT INTO Employee_Test VALUES (3,'Rakesh',1100);
INSERT INTO Employee_Test VALUES (4,'Manoj',1300);
INSERT INTO Employee_Test VALUES (5,'Amit',1400);
INSERT INTO Employee_Test VALUES (6,'Lokesh',1600);
INSERT INTO Employee_Test VALUES (7,'Maneneder',1400);
INSERT INTO Employee_Test VALUES (8,'Narendra',400);
INSERT INTO Employee_Test VALUES (9,'Kaushal',1900);
INSERT INTO Employee_Test VALUES (10,'Vikas',3400);
INSERT INTO Employee_Test VALUES (11,'Sudhir',800);
go
select * from Employee_Test
go
select * from Employee_Test emp1
where 1=(select COUNT(distinct(emp2.employee_salary))
from Employee_Test emp2
where emp2.Employee_Salary>=emp1.Employee_Salary
)
go